When sickle cell carrier marries a normal woman, the probability of them having a normal offspring is

  • A 0.75
  • B 0.25
  • C 0.5
  • D .1

The correct answer is C. 0.5

A sickle cell carrier (AS) and a normal woman (AA), when crossed will yield:

2 normal offsprings (AA) and 2 sickle cell carrier (AS).

Hence, the probability of a normal child = \(\frac{2}{4}\)

= \(0.5\)

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