Chlorine consisting of two isotope of mass number 35 and 37 in the ratio 3:1 has an atomic mass of 35.5. Calculate the relative abundance of the isotope of mass number 37

  • A 20
  • B 25
  • C 60
  • D 75
jamb 2015chemistry

The correct answer is B. 25

Let the relative abundance of the energy with mass 37 be

Total relative abundance of the isotope of mass 359100-k)

Total mass of isotope of mass 37-37x, while that of 35-359(100x)

-37x + 3500 − 35 − 35.5

-37x + 3500 − 35n − 35.5

Mean mass of chlorine atom − (2n + 3500)/ ÷ 100

= 35.5

2x + 3500 − 3550yx = 50/2

Previous question Next question