At 25oC and 1atm, a gas occupies a volume of 1.50dm3. What volume will it occupy at 100oC and 1atm?
The correct answer is A. 1.88 dm3
\(\frac{v_1}{T_1} = \frac{V_2}{T_2}\)
V2 = \(\frac{V_1 \times T_2}{T_1}\)
= \(\frac{1.50 \times 373}{298}\)
= 1.88 dm3
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