The relationship between the velocity (U) of gas molecules and their relative molecular mass (M) is shown by the equation

  • A U = (kM)\(\frac{1}{2}\)
  • B U = (kM)2
  • C U = \(\sqrt{\frac{k}{m}}\)
  • D U = \(\frac{k}{m}\)
jamb 1986chemistry

The correct answer is C. U = \(\sqrt{\frac{k}{m}}\)

The relationship between (U) of a gas molecule and the relative molecular mass is \(\bar{U}\) = (\(\frac{k}{m}\))\(^{\frac{1}{2}}\)

or \(\bar{U}\) = \(\sqrt{\frac{k}{m}}\)

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