The relative atomic mass of a naturally occurring lithium consisting of 90%\(\frac{7}{3}\)Li and 10%\(\frac{6}{3}\)Li is
The correct answer is D. 6.9
(\(\frac{90}{100}\) x 7) + (\(\frac{10}{100}\) x 6)
= 6.3 + 0.6 = 6.9
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