A given mass of gas occupies 2dm3 at 300k. At what temperature will its volume be doubled, keeping the pressure constant?

  • A 400k
  • B 480k
  • C 550k
  • D 600k
jamb 2017chemistry

The correct answer is D. 600k

At constant pressure connotes Charle's law

\(\frac{V_1}{T_1}\) = \(\frac{V_2}{T_2}\)

\(\frac{2dm^3}{300k}\) = 2 x \(\frac{2dm^3}{T_2}\)

T2= 600k

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