The concentration of a solution is given by the amount of solute divided by the total volume of the solution. In this case, the amount of sulphuric acid is 2.2 moles (since we have 1 litre of a 2.2M solution), and the total volume after mixing with water is 11 litres (1 litre of acid + 10 litres of water).

So, the resulting concentration (C) can be calculated as follows:

\(C = \frac{{\text{{amount of solute}}}}{{\text{{total volume of solution}}}} = \frac{{2.2 \, \text{{moles}}}}{{11 \, \text{{litres}}}} = 0.2 \, \text{{M}}\)

So, the correct answer is 0.2M