In the reaction between sodium hydroxide and sulphuric acid solutions, what volume of 0.5 molar sodium hydroxide would exactly neutralise 10cm3 of 1.25 molar sulphuric acid?

  • A 5cm\(^3\)
  • B 10cm\(^3\)
  • C 20cm\(^3\)
  • D 50cm\(^3\)
jamb 2018chemistry

The correct answer is D. 50cm\(^3\)

2NaOH + H\(_2\) SO\(_4\)↔Na\(_2\)SO\(_4\) + 2H\(_2\)O

  V x 0.5M = 2(10 x 1.25)

  0.5V = 2 x 12.5

  0.5V = 25

  V = 250.5 = 50cm\(^2\)

Correct computation as it follows the equation specified.

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