The hydrogen ion concentration of a sample of orange juice is 2.0 X 10\(^{-11}\)moldm\(^{-3}\). What is its p\(^{OH}\)? [log102 = 0.3010]

  • A 3.30
  • B 13.00
  • C 10.70
  • D 11.30
jamb 2018chemistry

The correct answer is A. 3.30

PH+POH=14

p\(^{H}\) = Log [H\(^+\)]

p[H\(^+\) ] = 2.0 X 10\(^{-11}\)moldm\(^{-3}\)

  p\(^{H}\) = Log [2.0 X 10\(^{-11}\)]

  p\(^{H}\) = 10.70

10.70+ p\(^{OH}\) =14

p\(^{OH}\) = 14 -10.70

= 3.30

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