The oxidation state(s) of nitrogen in ammonium nitrite is/are

  • A -3, +3
  • B +5
  • C -3, +5
  • D -3
jamb 2019chemistry

The correct answer is A. -3, +3

Ammonium nitrite = NH\(_4\)NO\(_2\)

NH\(_4 ^+\): Let the oxidation number of Nitrogen = x

x + 4 = 1 \(\implies\) x = 1 - 4

x = -3

NO\(_2 ^-\): x - 4 = -1

x = -1 + 4 \(\implies\) x = +3.

The oxidation numbers for Nitrogen in Ammonium Nitrite = -3, +3.

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