The emission of two successive beta particles from the nucleus \(^{32} _{15} P\) will produce

  • A \(^{30} _{14}\)Si
  • B \(^{32} _{13}\)Al
  • C \(^{32} _{17}\)Cl
  • D \(^{32} _{16}\)S
jamb 2019chemistry

The correct answer is C. \(^{32} _{17}\)Cl

\(^{32} _{15}\)P \(\to\) 2\(^{0} _{-1}\)e + \(^{a} _{b}\)X

32 = 2(0) + a

a = 32

15 = 2(-1) + b

b = 15 + 2

b = 17

\(\therefore\) \(^{a} _{b}\)X = \(^{32} _{17}\)Cl

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