An element Z contains 80% of \(^{16} _8\)Z and 20% of \(^{18} _8\)Z. Its relative atomic mass is

  • A 16.2
  • B 17.6
  • C 16.0
  • D 16.4
jamb 2019chemistry

The correct answer is D. 16.4

R.A.M of Z = \(16(\frac{80}{100}) + 18(\frac{20}{100})\)

= \(12.8 + 3.6\)

= 16.4

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