8g of CH\(_4\) occupies 11.2 at S.T.P. What volume would 22g of CH\(_3\)CH\(_2\)CH\(_3\) occupy under the same condition?

  • A 3.7dm\(^3\)
  • B 11.2dm\(^3\)
  • C 22.4dm\(^3\)
  • D 33dm\(^3\)
jamb 2020chemistry

The correct answer is B. 11.2dm\(^3\)

Molar mass of methane = 16g/mol

At S.T.P.       its 8g occupies 11.2

                    so 16g occupies 22.4 dm\(^3\)

Molar mass of propane = 44g/mol\(^-1\) occupies 22.4dm\(^3\) at S.T.P

                      so 22g will occupy 11.2dm\(^3\)

Previous question Next question