Calculate the solubility in mol dm-3 of 40g of CuSO4 dissolved in 100g of water at 120°C?

[Cu = 64, S = 32, O = 16]

  • A 4.00
  • B 2.50
  • C 0.40
  • D 0.25
jamb 2010chemistry

The correct answer is B. 2.50

Solubility = \(\frac{\text{number of moles of solution}}{\text{vol of solution}}\)

100g of water = 100 cm\(^3\) = 0.1 dm\(^3\).

CuSO\(_4\) = 160 g/mol

No of moles of CuSO\(_4\) in 40g = \(\frac{40}{160}\)

= 0.25 mol.

Solubility = \(\frac{0.25}{0.1}\)

= 2.5 moldm\(^{-3}\).

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