The relative atomic mass of a naturally occurring lithium consisting of 90% \(^7 _3\)Li and \(^6 _3\)10% Li is

  • A 6.9
  • B 7.1
  • C 6.2
  • D 6.8

The correct answer is A. 6.9

R.A.M = m\(_1 \alpha_1\) + m\(_2 \alpha_2\)

= 7(90/100) + 6(10/100)

= 6.3 + 0.6

= 6.9

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