If 10.8 g of silver is deposited in a silver coulometer volume of oxygen liberated is?

  • A 0.56 dm3
  • B 5.60 dm3
  • C 11.20 dm3
  • D 22.40 dm3

The correct answer is A. 0.56 dm3

Ag+ + e-

H = 108 g Ag

= 0.11 10.8 Ag

4OH → O2 + 2H2O + 4e

4F ↔ 1mole O2

4F = 22.4 dm3 χ 0.1 = 0.56 dm3

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