MnO-4 + 8H+ + ne → Mn++ + 4H2O. Which is the value of n in the reaction above?
The correct answer is D. 5
MnO-4 + 8H+ + ne- â Mn++ + 4H2O
Since Mn has 7 electrons on one side and 2 electrons on the other side. The value of ne- is 5.
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