How many grams of bromine will be required to completely react with 10 g of propyne?

(C = 12, H = 1, Br = 80)

  • A 20 g
  • B 40 g
  • C 60 g
  • D 80 g

The correct answer is D. 80 g

C3H4 + 2Br2 - C3Br4 + 2H2

(36 + 4) (4 X 80)

40 g of C3H4 reacts with 320 g of Br

10 " " will react with

(10)/(40) x (320) /(1) = 80g

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