If 100 cm3 of oxygen pass through a porous plug in 50 seconds, the time taken for the same volume of hydrogen to pass through the same porous plug is?

(O = 16, H = 1)

  • A 10.0 s
  • B 12.5 s
  • C 17.7 s
  • D 32.0 s
jamb 1992chemistry

The correct answer is B. 12.5 s

100 cm3 of O2 diffuse 50 sec

∴ 100 cm3 of H2 → (100) / (100) x (50) /(1)

t1 50 sec

molecular mass H+ → 2 x 1 = 2

molecular mass of O2 16 x 2 = 32

T2 = t1 √M2/M1 = t2 = 50 √2/32

50√0.625 = 50 x 0.25 = 12.5 secs

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