How many moles of oxygen molecules would be produced from the decomposition of 2.50 moles of potassium trioxochlorate (V)?

  • A 2.50
  • B 3.50
  • C 3.75
  • D 7.50

The correct answer is C. 3.75

2KClO3(s) → 2KCl(s) + 3O2(g)

From the above balanced equation, 2 moles of reactant decomposed to give 3 moles of O2 i.e.

i mole of reactant will produce (3)/(2) moles O2.

∴ 2.5 moles KClO3 will give

= 3.75 moles

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