Which is the temperature of a given mass of a gas initially at 0°C and 9 atm, if the pressure is reduced to 3 atm at constant volume?

  • A 91K
  • B 182K
  • C 273K
  • D 819K

The correct answer is A. 91K

From P1/T1 = P2/T2 = 9/273 = 3/T2

T2 x 9 = 273 x 3

T2 = (273 x 3)/9

T2 = 91K

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