How many moles HCL will be required to react with potassium heptaoxodichromate (VI) to produce 3 moles of chlorine?

  • A 14
  • B 12
  • C 11
  • D 10

The correct answer is A. 14

K\(_{2}\)Cr\(_{2}\)O\(_{7}\) + HCl  â†’ Cl\(_{2}\) + KCl + CrCl\(_{3}\) + H\(_{2}\)O

Balancing the equation, we have

K\(_{2}\)Cr\(_{2}\)O\(_{7}\) + 14HCl → 3Cl\(_{2}\) + 2KCl + 2CrCl\(_{3}\) + 7H\(_{2}\)O

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