How many moles HCL will be required to react with potassium heptaoxodichromate (VI) to produce 3 moles of chlorine?
The correct answer is A. 14
K\(_{2}\)Cr\(_{2}\)O\(_{7}\) + HCl â Cl\(_{2}\) + KCl + CrCl\(_{3}\) + H\(_{2}\)O
Balancing the equation, we have
K\(_{2}\)Cr\(_{2}\)O\(_{7}\) + 14HCl â 3Cl\(_{2}\) + 2KCl + 2CrCl\(_{3}\) + 7H\(_{2}\)O
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