The pOH of a solution of 0.25 mol dm-3 of hydrochloric acid is

  • A 12.40
  • B 13.40
  • C 14.40
  • D 14.60

The correct answer is B. 13.40

pOH = -log [2.5 * 10-1]

= -log[-0.3979 + 1]

= 13.40

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