(1/2)Zn2+(aq) + e- → (1/2) Zn(s)

In the reaction above, calculate the quantity of electricity required to discharge zinc.

[F = 96 500 C mol-1]

  • A 0.965 * 104C
  • B 4.820 * 104C
  • C 9.650 * 104C
  • D 48.200 * 104C

The correct answer is C. 9.650 * 104C

1 mol → 96500 * 2

0.5 mol → X

X = 0.5 * 96500 * 2

= 9.650 * 104C

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