An elements X with relative atomic mass 16.2 contains two isotopes 168X with relative abundance of 90% and m8X with relative abundance of 10%. The value of m is

An elements X with relative atomic mass 16.2 contains two isotopes 168X with relative abundance of 90% and m8X with relative abundance of 10%. The value of m is

An elements X with relative atomic mass 16.2 contains two isotopes ¹⁶₈X with relative abundance of 90% and ^m₈X with relative abundance of 10%. The value of m is

A 16
B 18
C 12
D 14

jamb 2001 chemistry

The correct answer is B. 18

¹⁶₈X, ^m₈X

16 * (90/100) + m * (10/100) = 16.2

1440 + 10m = 1620

10m = 180

m = 18

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