What current in amperes will deposit 2.7g of aluminium in 2 hours?

[Al = 27, F = 96 500 C mol-1]

  • A 32
  • B 8
  • C 4
  • D 16
jamb 2001chemistry

The correct answer is C. 4

Al3+ + 3e → Al

3 * 96500 → 27

I = 3600 * 2 → 27

I = (2.7/27) * ((3 * 96500)/(3600 * 2))

= 4.025 ≈ 4

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