A compound contains 31.91% potassium, 28.93% chlorine and the rest oxygen. What is the chemical formula of the compound?

[K = 39, Cl = 35.5, O = 16]

  • A KClO4
  • B KClO
  • C KClO2
  • D KClO3
jamb 2002chemistry

The correct answer is D. KClO3

K- (31.91%), Mole = 31.91/39 =0.8182

Cl-(28.93%), Mole = 28.93/35.5 = 0.815

O-(39.16%), Mole = 39.6/16 = 2.448

K = 0.8182/0.815 = 1

Cl = 0.815/0.815 = 1

O = 2.448/0.815 = 3

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