What amount of mercury would be liberated if the same quantity of electricity that liberates 0.65g of zinc is applied?

  • A 2.01g
  • B 1.00g
  • C 4.02g
  • D 8.04g
jamb 2002chemistry

The correct answer is A. 2.01g

Zn2+ + 2e- → Zn

2F will be liberated 65g of Zn, if 0.65gm of Zn is liberated, the quantity of electricity used

X = (0.65/65) * 2

= 0.02F

∴ Hg2+ + 2e- → Hg

i.e 2F → 201gm of Hg

∴ 0.02 will liberated

Y = (0.02/2) * 201

= 2.01g

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