The solubility of a salt of molar mass 101g at 20oC is 0.34 mol dm-3. If 3.40g of the salt is dissolved completely in 250cm3 of water in a beaker, the resulting solution is

  • A A suspension
  • B Saturated
  • C Unsaturated
  • D Supersaturated
jamb 2002chemistry

The correct answer is C. Unsaturated

At 20oC

0.34 mol/dm of the salt dissolve

= 0.34 * 101 = 34.34gm

Of the salt dissolved.

∴ 34.34gm dissolve is 1,000cm3

If only 250 cm3 is the required mass

X = (250/1000) * 34.34

= 8.555gm

If only 3.40gm of the salt dissolved ,the solution is unsaturated

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