When a group data is involved, cumulative frequency is used. The formula will be: Median=[(N+1)/2]th

  For member of odd number items. That is, where N is odd

  Median=([N/2]th + [N/2 + 1]th)/2

  For member of odd number items. That is, where N is odd

  Solution:

  From the table, there are 20 members as indicated by the cumulative frequency. Since the members are odd (10) the median age will be ([N/2]th + [N/2 + 1]th)/2

  Median=([10/2]th + [10/2 + 1]th)/2

  =(5th + 6th)/2

  The 5th member is 3 and the 6th member is on 3

  Median=(3 + 3)/2

  =6/2

  Median = 3