In a triangle XYZ, < YXZ = 44° and < XYZ = 112°. Calculate the acute angle between the internal bisectors of < XYZ and < XZY.

  • A 12°
  • B 56°
  • C 68°
  • D 78°

The correct answer is C. 68°

the acute angle between the internal bisectors of < XYZ and < XZY is 68°

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