A die has four of it's faces coloured white and the remaining two coloured black. What is the probability that when the die is thrown two consecutive time, the top face will be white in both cases?
The correct answer is C. \(\frac{4}{9}\)
The probability of the top face being white in a single throw is (\frac{4}{6} = \frac{2}{3}) since there are 4 white faces and 6 faces in total.
Since the two throws are independent events, the probability of the top face being white in both throws is (\left(\frac{2}{3}\right)^2 = \frac{4}{9}).
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