Let's simplify the expression \(\sqrt{48}\) - \(\frac{9}{\sqrt{3}}\) + \(\sqrt{75}\). We can start by simplifying the square roots. 

Recall that \(\sqrt{ab} = \sqrt{a} \times \sqrt{b}\) if \(a\) and \(b\) are positive numbers. 

Using this property, we can rewrite the square roots as follows: \(\sqrt{48} = \sqrt{16 \times 3} = 4\sqrt{3}\) and \(\sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3}\). 

Substituting these values into the expression, we get \(4\sqrt{3} - \frac{9}{\sqrt{3}} + 5\sqrt{3}\).

Now, let's simplify the fraction. Recall that to rationalize a fraction with a square root in the denominator, we can multiply both the numerator and denominator by the square root. In this case, we can multiply both the numerator and denominator of the fraction by \(\sqrt{3}\) to get \(\frac{9}{\sqrt{3}} = \frac{9}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{9\sqrt{3}}{\sqrt{3}^2} = 3\sqrt{3}\). Substituting this value into the expression, we get \(4\sqrt{3} - 3\sqrt{3} + 5\sqrt{3}\).

Finally, we can combine like terms to get \(4\sqrt{3} - 3\sqrt{3} + 5\sqrt{3} = (4 - 3 + 5)\sqrt{3} = 6\sqrt{3}\). So, the simplified form of the expression is 6√3