What is the n-th term of the sequence 2, 6, 12, 20...?

  • A 4n - 2
  • B 2(3n - 1)
  • C \(n^2\) + n
  • D \(n^2\) + 3n + 2
jamb 2021mathematics

The correct answer is C. \(n^2\) + n

Given that 2, 6, 12, 20...? the nth term = n\(^2\) + n

check: n = 1, u1 = 2

n = 2, u2 = 4 + 2 = 6

n = 3, u3 = 9 + 3 = 12

∴ n = 4, u4 = 16 + 4 = 20

Previous question Next question