Sure! Let's substitute the given values of \(x\) and \(y\) into the expression and evaluate it:

Given expression: \(\frac{xy^2 - x^2y}{x^2 - xy}\)

Substitute \(x = -2\) and \(y = 3\) into the expression:

\(\frac{(-2)(3^2) - (-2)^2(3)}{(-2)^2 - (-2)(3)}\)

Now, calculate the values within the expression:

\(\frac{-18 - 12}{4 + 6}\)

\(\frac{-30}{10}=-3\)

So, when \(x = -2\) and \(y = 3\), the value of the expression is \(-3\).