We are given the equation (x - 2)(x - 3) = 12 and asked to solve for x. Expanding the left side of the equation, we get:

x^2 - 3x - 2x + 6 = 12

x^2 - 5x - 6 = 0

Factoring this quadratic equation, we get:

(x + 1)(x - 6) = 0

So, the solutions to this equation are x = -1 and x = 6. Therefore, the values of x that satisfy the given equation are **-1 and 6**.