Three brothers in a business deal share the profit at the end of a contract. The first received \(\frac{1}{3}\) of the profit and the second \(\frac{2}{3}\) of the remainder. If the third received the remaining N12000.00 how much profit did they share?
The correct answer is B. N54 000.00
Let's break down the information given step by step:
1. The first brother received \(\frac{1}{3}\) of the profit.
2. The second brother received \(\frac{2}{3}\) of the remainder after the first brother.
3. The third brother received the remaining N12000.00.
Let's assume the total profit is represented by \(P\).
1. First brother received: \(\frac{1}{3}P\) profit.
2. After the first brother, the remaining profit: \(P - \frac{1}{3}P = \frac{2}{3}P\).
3. Second brother received: \(\frac{2}{3} \cdot \frac{2}{3}P = \frac{4}{9}P\) profit.
4. Third brother received: Remaining profit = Total profit - Profit taken by first and second brothers
5. Third brother received: \(P - \left(\frac{1}{3}P + \frac{4}{9}P\right) = P - \frac{7}{9}P = \frac{2}{9}P\).
Given that the third brother received N12000.00, we can set up an equation to solve for the total profit \(P\):
\(\frac{2}{9}P = 12000\)
Multiply both sides by \(\frac{9}{2}\):
\[P = 12000 \cdot \frac{9}{2} = 54000\]
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