If a = 2, b = -2 and c = -\(\frac{1}{2}\), evaluate (\(ab^2- bc^2)(a^2c - abc)\)

  • A 2
  • B -28
  • C -30
  • D -34
jamb 1990mathematics

The correct answer is D. -34

(ab

- bc

)(a

c - abc)

[2(2)

- (- 2x\(\frac{1}{2}\))] [2

(-\(\frac{1}{2}\)) - 2(-2)(-\(\frac{1}{2}\))]

[8 = \(\frac{1}{2}\)][-2 - 2] = \(\frac{17}{2}\) x 4

= -34

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