What must be added to 4x\(^2\)- 4 to make it a perfect square?

  • A \(\frac{-1}{x^2}\)
  • B \(\frac{1}{x^2}\)
  • C 1
  • D -1
jamb 1990mathematics

The correct answer is B. \(\frac{1}{x^2}\)

(2x \(\frac{-1}{4}\)^2(2x \(\frac{-1}{4}\) = 4x 2= 4x + \(\frac{1}{x^2}\) - 4 what must be added is +\(\frac{1}{x^2}\)

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