A car painter charges N40.00 per day for himself and N10.00 per day for his assistant. if a fleet of cars were painted for N2000.00 and the painter worked 10days more than his assistant, how much did the assistant receive?
The correct answer is B. N320.00
Let's denote the number of days the assistant worked as \(x\). Since the painter worked 10 days more than the assistant, the number of days the painter worked is \(x + 10\).
The painter charges N40.00 per day, so the amount the painter earned is \(40 \times (x + 10)\).
The assistant charges N10.00 per day, so the amount the assistant earned is \(10x\).
Given that the total amount earned is N2000.00, we can set up an equation:
\(40 \times (x + 10) + 10x = 2000\)
Simplify the equation:
\(40x + 400 + 10x = 2000\)
Combine like terms:
\(50x + 400 = 2000\)
Subtract 400 from both sides:
\(50x = 1600\)
Divide by 50:
\(x = 32\)
So, the assistant worked for 32 days. Now we can calculate the amount the assistant received:
\(10x = 10 \times 32 = 320\)
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