To simplify the given expression \(\sqrt[3]{(64r^{-6})^{\frac{1}{2}}}\), let's break it down step by step:

1. First, simplify the exponent inside the parentheses:
  \((64r^{-6})^{\frac{1}{2}} = \sqrt{64r^{-6}}\)
  
2. Simplify under the square root:
  \(\sqrt{64r^{-6}} = 8r^{-3}\)
  
3. Now, take the cube root of \(8r^{-3}\):
  \(\sqrt[3]{8r^{-3}} = 2r^{-1} = \frac{2}{r}\)

So, the simplified expression is \(\frac{2}{r}\)