For what values of x is the curve y = \(\frac{x^2 + 3}{x + 4}\) decreasing?

  • A -3
  • B -3 \(\geq\) x
  • C 0
  • D 0 \(\leq\) x \(\leq\) 3

The correct answer is D. 0 \(\leq\) x \(\leq\) 3

No explanation given
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