The solution of the quadratic equation px²+ qx + b = 0 is

  • A \(\sqrt{\frac{-b \pm b^2 - 4ac}{2a}}\)
  • B \(\frac{-b \pm \sqrt{ p^2 - 4pb}}{2a}\)
  • C \(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)
  • D \(\frac{-q \pm \sqrt{ p^2 - 4bp}}{2p}\)
jamb 1988mathematics

The correct answer is C. \(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)

px²+ qx + b = 0

Using almighty formula

\(\frac{-b \pm \sqrt{ b^2 - 4ac}}{2a}\).........(i)

Where a = p, b = q and c = b

substitute for this value in equation (i)

= \(\frac{-q \pm \sqrt{ q^2 - 4bp}}{2p}\)

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