Two chords QR and NP of a circle intersect inside the circle at x. If RQP = 37°, RQN = 49° and QPN = 35°, find PRQ

  • A 35°
  • B 37°
  • C 49°
  • D 59°
jamb 1987mathematics

The correct answer is D. 59°

In PNO, ONP

= 180 - (35 + 86)

= 180 - 121

= 59°

PRQ = QNP = 59°(angles in the same segment of a circle are equal)

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