If x varies directly as \(y^3\) and x = 2 when y = 1, find x when y = 5
 

  • A 2
  • B 10
  • C 125
  • D 250

The correct answer is D. 250

Since x varies directly as \(y^3\), we can write the relationship between x and y as x = ky^3, where k is the constant of variation. We are given that x = 2 when y = 1, so we can use this information to find the value of k:

x = ky^3
=> 2 = k(1)^3
=> k = 2

Now that we know the value of k, we can use the relationship x = ky^3 to find the value of x when y = 5:

x = ky^3

=> x = 2(5)^3

=> x = 250

Hence, when y = 5, the value of x is 250.

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