If y = \(\frac{x}{x - 3}\) + \(\frac{x}{x + 4}\) find y when x = -2
The correct answer is A. -\(\frac{3}{5}\)
Given that y = \(\frac{x}{x - 3}\) + \(\frac{x}{x + 4}\), we can find the value of y when x = -2 by substituting x = -2 into the expression for y:
y = \(\frac{x}{x - 3}\) + \(\frac{x}{x + 4}\)
=> y = \(\frac{-2}{-2 - 3}\) + \(\frac{-2}{-2 + 4}\)
=> y = \(\frac{-2}{-5}\) + \(\frac{-2}{2}\)
=> y = \(\frac{2}{5}\) - 1
=> y = -\(\frac{3}{5}\)
Hence, when x = -2, the value of y is -\(\frac{3}{5}\).
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