Solve the simultaneous equations 2x - 3y = -10,  10x - 6y = -5
 

  • A x = 2\(\frac{1}{2}\), y = 5
  • B x = \(\frac{1}{2}\), y = \(\frac{3}{2}\)
  • C x = 2\(\frac{1}{4}\), y = 3\(\frac{1}{2}\)
  • D x = 2\(\frac{1}{3}\), y = 3\(\frac{1}{2}\)
  • E x = 2\(\frac{1}{3}\), y = 2\(\frac{1}{2}\)
jamb 1985mathematics

The correct answer is A. x = 2\(\frac{1}{2}\), y = 5

The given system of equations is:
\(2x - 3y = -10\)

\(10x - 6y = -5\)

Multiplying the first equation by 5, we get:
\(10x - 15y = -50\)

Subtracting this equation from the second equation, we get:

\((10x - 6y) - (10x - 15y) = -5 + 50\)

\(9y = 45\)

So, y = 5.

Substituting this value of y into the first equation, we get:
\(2x - 3(5) = -10\)

Solving this equation, we get:

\(2x = 5\)

So, x = \(\frac{5}{2}\).

Therefore, the correct answer is x = 2\(\frac{1}{2}\), y = 5.

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