In \(\bigtriangleup\)XYZ, XY = 3cm, XZ = 5cm and YZ = 7cm. If the bisector of XYZ meets XZ at W, what is the length of XW?
The correct answer is A. 1.5cm
In \(\bigtriangleup\)XYZ, let's use the Angle Bisector Theorem to find the length of XW.
The Angle Bisector Theorem states that if a ray bisects an angle of a triangle, then it divides the opposite side into two segments that are proportional to the other two sides of the triangle.
In this case, since W is on XZ and XY = 3cm and YZ = 7cm, we have \(\frac{XW}{ZW} = \frac{XY}{YZ} = \frac{3}{7}\).
Since XZ = 5cm, we can write XW + ZW = 5cm. Substituting ZW = \(\frac{7}{3}\)XW, we get:
XW + \(\frac{7}{3}\)XW = 5cm.
Solving for XW, we get:
XW = \(\frac{15}{10}\)cm = 1.5cm.
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