Two cars X and Y start at the same point and travel towards a point P which is 150km away. If the average speed of Y is 60km per hour and x arrives at P 25 minutes earlier than Y. What is the average speed of X?
The correct answer is B. 72km per hour
Let's solve this problem step by step:
1. Since car Y travels at an average speed of 60km per hour, it takes \(\frac{150}{60}\) = 2.5 hours to reach point P.
2. Since car X arrives at point P 25 minutes earlier than car Y, it takes 2.5 - \(\frac{25}{60}\) = 2.0833 hours to reach point P.
3. Since the distance between the starting point and point P is 150km, the average speed of car X is \(\frac{150}{2.0833}\) ≈ 72km per hour.
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